Optimal. Leaf size=176 \[ \frac {a^3 (38 B+45 C) \sin (c+d x)}{15 d}+\frac {a^3 (43 B+45 C) \sin (c+d x) \cos ^2(c+d x)}{60 d}+\frac {a^3 (13 B+15 C) \sin (c+d x) \cos (c+d x)}{8 d}+\frac {(7 B+5 C) \sin (c+d x) \cos ^3(c+d x) \left (a^3 \sec (c+d x)+a^3\right )}{20 d}+\frac {1}{8} a^3 x (13 B+15 C)+\frac {a B \sin (c+d x) \cos ^4(c+d x) (a \sec (c+d x)+a)^2}{5 d} \]
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Rubi [A] time = 0.45, antiderivative size = 176, normalized size of antiderivative = 1.00, number of steps used = 8, number of rules used = 7, integrand size = 40, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.175, Rules used = {4072, 4017, 3996, 3787, 2635, 8, 2637} \[ \frac {a^3 (38 B+45 C) \sin (c+d x)}{15 d}+\frac {a^3 (43 B+45 C) \sin (c+d x) \cos ^2(c+d x)}{60 d}+\frac {a^3 (13 B+15 C) \sin (c+d x) \cos (c+d x)}{8 d}+\frac {(7 B+5 C) \sin (c+d x) \cos ^3(c+d x) \left (a^3 \sec (c+d x)+a^3\right )}{20 d}+\frac {1}{8} a^3 x (13 B+15 C)+\frac {a B \sin (c+d x) \cos ^4(c+d x) (a \sec (c+d x)+a)^2}{5 d} \]
Antiderivative was successfully verified.
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Rule 8
Rule 2635
Rule 2637
Rule 3787
Rule 3996
Rule 4017
Rule 4072
Rubi steps
\begin {align*} \int \cos ^6(c+d x) (a+a \sec (c+d x))^3 \left (B \sec (c+d x)+C \sec ^2(c+d x)\right ) \, dx &=\int \cos ^5(c+d x) (a+a \sec (c+d x))^3 (B+C \sec (c+d x)) \, dx\\ &=\frac {a B \cos ^4(c+d x) (a+a \sec (c+d x))^2 \sin (c+d x)}{5 d}+\frac {1}{5} \int \cos ^4(c+d x) (a+a \sec (c+d x))^2 (a (7 B+5 C)+a (2 B+5 C) \sec (c+d x)) \, dx\\ &=\frac {a B \cos ^4(c+d x) (a+a \sec (c+d x))^2 \sin (c+d x)}{5 d}+\frac {(7 B+5 C) \cos ^3(c+d x) \left (a^3+a^3 \sec (c+d x)\right ) \sin (c+d x)}{20 d}+\frac {1}{20} \int \cos ^3(c+d x) (a+a \sec (c+d x)) \left (a^2 (43 B+45 C)+2 a^2 (11 B+15 C) \sec (c+d x)\right ) \, dx\\ &=\frac {a^3 (43 B+45 C) \cos ^2(c+d x) \sin (c+d x)}{60 d}+\frac {a B \cos ^4(c+d x) (a+a \sec (c+d x))^2 \sin (c+d x)}{5 d}+\frac {(7 B+5 C) \cos ^3(c+d x) \left (a^3+a^3 \sec (c+d x)\right ) \sin (c+d x)}{20 d}-\frac {1}{60} \int \cos ^2(c+d x) \left (-15 a^3 (13 B+15 C)-4 a^3 (38 B+45 C) \sec (c+d x)\right ) \, dx\\ &=\frac {a^3 (43 B+45 C) \cos ^2(c+d x) \sin (c+d x)}{60 d}+\frac {a B \cos ^4(c+d x) (a+a \sec (c+d x))^2 \sin (c+d x)}{5 d}+\frac {(7 B+5 C) \cos ^3(c+d x) \left (a^3+a^3 \sec (c+d x)\right ) \sin (c+d x)}{20 d}+\frac {1}{4} \left (a^3 (13 B+15 C)\right ) \int \cos ^2(c+d x) \, dx+\frac {1}{15} \left (a^3 (38 B+45 C)\right ) \int \cos (c+d x) \, dx\\ &=\frac {a^3 (38 B+45 C) \sin (c+d x)}{15 d}+\frac {a^3 (13 B+15 C) \cos (c+d x) \sin (c+d x)}{8 d}+\frac {a^3 (43 B+45 C) \cos ^2(c+d x) \sin (c+d x)}{60 d}+\frac {a B \cos ^4(c+d x) (a+a \sec (c+d x))^2 \sin (c+d x)}{5 d}+\frac {(7 B+5 C) \cos ^3(c+d x) \left (a^3+a^3 \sec (c+d x)\right ) \sin (c+d x)}{20 d}+\frac {1}{8} \left (a^3 (13 B+15 C)\right ) \int 1 \, dx\\ &=\frac {1}{8} a^3 (13 B+15 C) x+\frac {a^3 (38 B+45 C) \sin (c+d x)}{15 d}+\frac {a^3 (13 B+15 C) \cos (c+d x) \sin (c+d x)}{8 d}+\frac {a^3 (43 B+45 C) \cos ^2(c+d x) \sin (c+d x)}{60 d}+\frac {a B \cos ^4(c+d x) (a+a \sec (c+d x))^2 \sin (c+d x)}{5 d}+\frac {(7 B+5 C) \cos ^3(c+d x) \left (a^3+a^3 \sec (c+d x)\right ) \sin (c+d x)}{20 d}\\ \end {align*}
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Mathematica [A] time = 0.46, size = 108, normalized size = 0.61 \[ \frac {a^3 (60 (23 B+26 C) \sin (c+d x)+480 (B+C) \sin (2 (c+d x))+170 B \sin (3 (c+d x))+45 B \sin (4 (c+d x))+6 B \sin (5 (c+d x))+780 B c+780 B d x+120 C \sin (3 (c+d x))+15 C \sin (4 (c+d x))+900 C d x)}{480 d} \]
Antiderivative was successfully verified.
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fricas [A] time = 0.48, size = 110, normalized size = 0.62 \[ \frac {15 \, {\left (13 \, B + 15 \, C\right )} a^{3} d x + {\left (24 \, B a^{3} \cos \left (d x + c\right )^{4} + 30 \, {\left (3 \, B + C\right )} a^{3} \cos \left (d x + c\right )^{3} + 8 \, {\left (19 \, B + 15 \, C\right )} a^{3} \cos \left (d x + c\right )^{2} + 15 \, {\left (13 \, B + 15 \, C\right )} a^{3} \cos \left (d x + c\right ) + 8 \, {\left (38 \, B + 45 \, C\right )} a^{3}\right )} \sin \left (d x + c\right )}{120 \, d} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 0.47, size = 210, normalized size = 1.19 \[ \frac {15 \, {\left (13 \, B a^{3} + 15 \, C a^{3}\right )} {\left (d x + c\right )} + \frac {2 \, {\left (195 \, B a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{9} + 225 \, C a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{9} + 910 \, B a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{7} + 1050 \, C a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{7} + 1664 \, B a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} + 1920 \, C a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} + 1330 \, B a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} + 1830 \, C a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} + 765 \, B a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 735 \, C a^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right )}}{{\left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} + 1\right )}^{5}}}{120 \, d} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 2.08, size = 223, normalized size = 1.27 \[ \frac {\frac {a^{3} B \left (\frac {8}{3}+\cos ^{4}\left (d x +c \right )+\frac {4 \left (\cos ^{2}\left (d x +c \right )\right )}{3}\right ) \sin \left (d x +c \right )}{5}+C \,a^{3} \left (\frac {\left (\cos ^{3}\left (d x +c \right )+\frac {3 \cos \left (d x +c \right )}{2}\right ) \sin \left (d x +c \right )}{4}+\frac {3 d x}{8}+\frac {3 c}{8}\right )+3 a^{3} B \left (\frac {\left (\cos ^{3}\left (d x +c \right )+\frac {3 \cos \left (d x +c \right )}{2}\right ) \sin \left (d x +c \right )}{4}+\frac {3 d x}{8}+\frac {3 c}{8}\right )+C \,a^{3} \left (2+\cos ^{2}\left (d x +c \right )\right ) \sin \left (d x +c \right )+a^{3} B \left (2+\cos ^{2}\left (d x +c \right )\right ) \sin \left (d x +c \right )+3 C \,a^{3} \left (\frac {\cos \left (d x +c \right ) \sin \left (d x +c \right )}{2}+\frac {d x}{2}+\frac {c}{2}\right )+a^{3} B \left (\frac {\cos \left (d x +c \right ) \sin \left (d x +c \right )}{2}+\frac {d x}{2}+\frac {c}{2}\right )+C \,a^{3} \sin \left (d x +c \right )}{d} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 0.34, size = 213, normalized size = 1.21 \[ \frac {32 \, {\left (3 \, \sin \left (d x + c\right )^{5} - 10 \, \sin \left (d x + c\right )^{3} + 15 \, \sin \left (d x + c\right )\right )} B a^{3} - 480 \, {\left (\sin \left (d x + c\right )^{3} - 3 \, \sin \left (d x + c\right )\right )} B a^{3} + 45 \, {\left (12 \, d x + 12 \, c + \sin \left (4 \, d x + 4 \, c\right ) + 8 \, \sin \left (2 \, d x + 2 \, c\right )\right )} B a^{3} + 120 \, {\left (2 \, d x + 2 \, c + \sin \left (2 \, d x + 2 \, c\right )\right )} B a^{3} - 480 \, {\left (\sin \left (d x + c\right )^{3} - 3 \, \sin \left (d x + c\right )\right )} C a^{3} + 15 \, {\left (12 \, d x + 12 \, c + \sin \left (4 \, d x + 4 \, c\right ) + 8 \, \sin \left (2 \, d x + 2 \, c\right )\right )} C a^{3} + 360 \, {\left (2 \, d x + 2 \, c + \sin \left (2 \, d x + 2 \, c\right )\right )} C a^{3} + 480 \, C a^{3} \sin \left (d x + c\right )}{480 \, d} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 5.60, size = 247, normalized size = 1.40 \[ \frac {\left (\frac {13\,B\,a^3}{4}+\frac {15\,C\,a^3}{4}\right )\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^9+\left (\frac {91\,B\,a^3}{6}+\frac {35\,C\,a^3}{2}\right )\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^7+\left (\frac {416\,B\,a^3}{15}+32\,C\,a^3\right )\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^5+\left (\frac {133\,B\,a^3}{6}+\frac {61\,C\,a^3}{2}\right )\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^3+\left (\frac {51\,B\,a^3}{4}+\frac {49\,C\,a^3}{4}\right )\,\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}{d\,\left ({\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^{10}+5\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^8+10\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^6+10\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^4+5\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2+1\right )}+\frac {a^3\,\mathrm {atan}\left (\frac {a^3\,\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )\,\left (13\,B+15\,C\right )}{4\,\left (\frac {13\,B\,a^3}{4}+\frac {15\,C\,a^3}{4}\right )}\right )\,\left (13\,B+15\,C\right )}{4\,d} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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